4^x+6=64^2x-3

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Solution for 4^x+6=64^2x-3 equation: 



4^x+6=64^2x-3

We move all terms to the left:

4^x+6-(64^2x-3)=0

We get rid of parentheses

4^x-64^2x+3+6=0

We add all the numbers together, and all the variables

4^x-64^2x+9=0

We move all terms containing x to the left, all other terms to the right

4^x-64^2x=-9

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